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參數(shù)資料
| 型號： | PS2604 |
| 廠商： | NEC Corp. |
| 英文描述： | Optocoupler Applications |
| 中文描述： | 光耦應用 |
| 文件頁數(shù)： | 16/38頁 |
| 文件大小： | 223K |
| 代理商： | PS2604 |
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15
I
CBL
I
CBL-
I
1
R
BE
I
1
V
BE
' V
(
1 -
)
................ (5)
I
C
h
FE
I
CBL
R
BE
As h
FE
' is equal to h
FE
if I
F
= approx. 5 mA, I
C
= approx. 15 mA, and R
BC
> 100 k
, expression (5) is simplified as follows:
' V
................ (6)
I
C
I
CBL
R
BE
I
C'
= h
FE
' (I
CBL
-I
1
) = h
FE
'
(
I
CBL
-
)
I
C'
= h
FE
'
I
CBL
(
1 -
................ (4)
I
CBL
R
BE
Note
I
C
'
h
FE
'
: Output current of an optocoupler having R
BE
: Amplification factor of an optocoupler having R
BE
Accordingly, the ratio of output current IC' (of the optocoupler having R
BE
) to output current IC (of the optocoupler with the base
open) is expressed by:
REDUCTION OF CURRENT TRANSFER RATIO (CTR) BY INSERTION OF BASE-
EMITTER RESISTOR
A resistor (R
BE
) connected to the base and emitter pins of an optocoupler causes the reduction of the output current (reduction of
current transfer ratio). This is because a part (I
1
) of the base current flows through the base-emitter resistor and causes a voltage
equivalent to the emitter-base voltage (V
BE
). The base current is reduced by this current component (I
1
) and, as the result, the
current transfer ratio (C
TR
) goes down. The output current I
C
' is expressed as follows:
V
BE
R
BE
V
BE
I
C
' h
FE
BE
I
BE
Figure 3-2.
相關PDF資料 |
PDF描述 |
|---|---|
| PS2604L | Optocoupler Applications |
| PS2602 | Optocoupler Applications |
| PS2602L | Optocoupler Applications |
| PS2605 | Optocoupler Applications |
| PS2605L | Optocoupler Applications |
相關代理商/技術參數(shù) |
參數(shù)描述 |
|---|---|
| PS2604L | 制造商:NEC 制造商全稱:NEC 功能描述:Optocoupler Applications |
| PS2605 | 制造商:California Eastern Laboratories (CEL) 功能描述:6pin DIP,Single Tr, AC, Base, Coupler |
| PS2605L | 制造商:NEC 制造商全稱:NEC 功能描述:Optocoupler Applications |
| PS2606 | 制造商:NEC 制造商全稱:NEC 功能描述:Optocoupler Applications |
| PS2606L | 制造商:NEC 制造商全稱:NEC 功能描述:Optocoupler Applications |
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