參數(shù)資料
型號: ISL6565BCRZ
廠商: INTERSIL CORP
元件分類: 穩(wěn)壓器
英文描述: Multi-Phase PWM Controller with Precision rDS(ON) or DCR Current Sensing for VR10.X Application
中文描述: SWITCHING CONTROLLER, 1500 kHz SWITCHING FREQ-MAX, PQCC28
封裝: 5 X 5 MM, ROHS COMPLIANT, PLASTIC, MO-220VHHD, QFN-28
文件頁數(shù): 23/28頁
文件大?。?/td> 722K
代理商: ISL6565BCRZ
23
Since the system poles and zero are affected by the values
of the components that are meant to compensate them, the
solution to the system equation becomes fairly complicated.
Fortunately, there is a simple approximation that comes very
close to an optimal solution. Treating the system as though it
were a voltage-mode regulator, by compensating the L-C
poles and the ESR zero of the voltage-mode approximation,
yields a solution that is always stable with very close to ideal
transient performance.
Select a target bandwidth for the compensated system, f
0
.
The target bandwidth must be large enough to assure
adequate transient performance, but smaller than 1/3 of the
per-channel switching frequency. The values of the
compensation components depend on the relationships of f
0
to the L-C pole frequency and the ESR zero frequency. For
each of the following three, there is a separate set of
equations for the compensation components.
.
Case 3:
In Equations 40, L is the per-channel filter inductance
divided by the number of active channels; C is the sum total
of all output capacitors; ESR is the equivalent-series
resistance of the bulk output-filter capacitance; and V
PP
is
the peak-to-peak sawtooth signal amplitude as described in
Figure 6 and
Electrical Specifications
.
Once selected, the compensation values in Equations 40
assure a stable converter with reasonable transient
performance. In most cases, transient performance can be
improved by making adjustments to R
C
. Slowly increase the
value of R
C
while observing the transient performance on an
oscilloscope until no further improvement is noted. Normally,
C
C
will not need adjustment. Keep the value of C
C
from
Equations 40 unless some performance issue is noted.
The optional capacitor C
2
, is sometimes needed to bypass
noise away from the PWM comparator (see Figure 17). Keep
a position available for C
2
, and be prepared to install a high-
frequency capacitor of between 22pF and 150pF in case any
leading-edge jitter problem is noted.
Output Filter Design
The output inductors and the output capacitor bank together
to form a low-pass filter responsible for smoothing the
pulsating voltage at the phase nodes. The output filter also
must provide the transient energy until the regulator can
respond. Because it has a low bandwidth compared to the
switching frequency, the output filter limits the system
transient response. The output capacitors must supply or
sink load current while the current in the output inductors
increases or decreases to meet the demand.
In high-speed converters, the output capacitor bank is usually
the most costly (and often the largest) part of the circuit.
Output filter design begins with minimizing the cost of this part
of the circuit. The critical load parameters in choosing the
output capacitors are the maximum size of the load step,
I,
the load-current slew rate, di/dt, and the maximum allowable
output-voltage deviation under transient loading,
V
MAX
.
Capacitors are characterized according to their capacitance,
ESR, and ESL (equivalent series inductance).
At the beginning of the load transient, the output capacitors
supply all of the transient current. The output voltage will
initially deviate by an amount approximated by the voltage
drop across the ESL. As the load current increases, the
voltage drop across the ESR increases linearly until the load
current reaches its final value. The capacitors selected must
FIGURE 17. COMPENSATION CONFIGURATION FOR
LOAD-LINE REGULATED ISL6565A, ISL6565B
CIRCUIT
I
COMP
C
C
R
C
R
FB
FB
VDIFF
-
+
V
DROOP
C
2
(OPTIONAL)
2
π
LC
-------1
f
0
>
R
C
R
FB
2
π
f
V
LC
0.75V
IN
0.75V
2
π
V
PP
R
FB
f
0
-----------------------------------
=
C
C
------------------------------------
=
Case 1:
2
π
LC
--------1
f
0
2
C ESR
)
------------1
<
R
C
R
FB
V
2
π
IN
0.75V
)
2
f
02
V
PP
R
FB
LC
(
)
2
f
0
2
LC
-----------0.75 V
=
C
C
2
π
(
------------------------------------------------------------
=
Case 2:
(EQ. 40)
f
0
π
C ESR
)
2
>
R
C
R
FB
2
π
f
V
L
IN
ESR
(
)
0.75 V
=
C
C
0.75V
ESR
2
π
V
PP
R
FB
f
0
L
-------------------------------------------- C
=
ISL6565A, ISL6565B
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