參數(shù)資料
型號(hào): LM6172AMWGRQML
廠商: NATIONAL SEMICONDUCTOR CORP
元件分類: 音頻/視頻放大
英文描述: VIDEO AMPLIFIER, CDSO16
封裝: CERAMIC, SOIC-16
文件頁(yè)數(shù): 5/21頁(yè)
文件大小: 635K
代理商: LM6172AMWGRQML
Power Supply Bypassing (Continued)
Termination
In high frequency applications, reflections occur if signals
are not properly terminated.
Figure 6 shows a properly termi-
nated signal while
Figure 7 shows an improperly terminated
signal.
To minimize reflection, coaxial cable with matching charac-
teristic impedance to the signal source should be used. The
other end of the cable should be terminated with the same
value terminator or resistor. For the commonly used cables,
RG59 has 75
characteristic impedance, and RG58 has
50
characteristic impedance.
Power Dissipation
The maximum power allowed to dissipate in a device is de-
fined as:
P
D = (TJ(max) TA)/θJA
Where P
D is the power dissipation in a device
T
J(max) is the maximum junction temperature
T
A is the ambient temperature
θ
JA is the thermal resistance of a particular package
For example, for the LM6172 in a SO-8 package, the maxi-
mum power dissipation at 25C ambient temperature is
780 mW.
Thermal resistance,
θ
JA, depends on parameters such as
die size, package size and package material. The smaller
the die size and package, the higher
θ
JA becomes. The 8-pin
DIP package has a lower thermal resistance (95C/W) than
that of 8-pin SO (160C/W). Therefore, for higher dissipation
capability, use an 8-pin DIP package.
The total power dissipated in a device can be calculated as:
P
D = PQ +PL
P
Q is the quiescent power dissipated in a device with no load
connected at the output. P
L is the power dissipated in the de-
vice with a load connected at the output; it is not the power
dissipated by the load.
Furthermore,
P
Q:
=
supply current x total supply voltage with no load
P
L:
=
output current x (voltage difference between sup-
ply voltage and output voltage of the same supply)
For example, the total power dissipated by the LM6172 with
V
S = ±15V and both channels swinging output voltage of
10V into 1 k
is
P
D:
=
P
Q +PL
:
=
2[(2.3 mA)(30V)] + 2[(10 mA)(15V 10V)]
:
=
138 mW + 100 mW
:
=
238 mW
DS012581-47
FIGURE 5. Power Supply Bypassing
DS012581-53
FIGURE 6. Properly Terminated Signal
DS012581-54
FIGURE 7. Improperly Terminated Signal
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