參數(shù)資料
型號(hào)： LT1376HVCS8
廠商： LINEAR TECHNOLOGY CORP
元件分類(lèi)： 穩(wěn)壓器
英文描述： RADIATION HARDENED HIGH EFFICIENCY, 5 AMP SWITCHING REGULATORS
中文描述： 3 A SWITCHING REGULATOR, 570 kHz SWITCHING FREQ-MAX, PDSO8
封裝： 0.150 INCH, PLASTIC, SOP-8
文件頁(yè)數(shù)： 25/28頁(yè)
文件大?。?/td> 232K
代理商： LT1376HVCS8
25
LT1375/LT1376
APPLICATIO
S I
FOR
ATIO
U
INDUCTOR VALUE
W
U
U
Unlike buck converters, positive-to-negative converters
cannot use large inductor values to reduce output ripple
voltage. At 500kHz, values larger than 25
μ
H make almost
no change in output ripple. The graph in Figure 19 shows
peak-to-peak output ripple voltage for a 5V to –5V con-
verter versus inductor value. The criteria for choosing the
inductor is therefore typically based on ensuring that peak
switch current rating is not exceeded. This gives the
lowest value of inductance that can be used, but in some
cases (lower output load currents) it may give a value that
creates unnecessarily high output ripple voltage. A com-
promise value is often chosen that reduces output ripple.
As you can see from the graph, largeinductors will not
give arbitrarily low ripple, but smallinductors can give
high ripple.
INDUCTOR SIZE (
μ
H)
0
O
P
)
150
120
90
60
30
0
20
1375/76 F19
5
10
15
25
5V TO –5V CONVERTER
OUTPUT CAPACITOR
ESR = 0.1
I
LOAD
= 0.25A
I
LOAD
= 0.1A
Figure 19. Ripple Voltage on Positive-to-Negative Converter
The difficulty in calculating the minimum inductor size
needed is that you must first know whether the switcher
will be in continuous or discontinuous mode at the critical
point where switch current is 1.5A. The first step is to use
the following formula to calculate the load current where
the switcher must use continuous mode. If your load
current is less than this, use the discontinuous mode
formula to calculate minimum inductor needed. If load
current is higher, use the continuous mode formula.
Output current where continuous mode is needed:
I
V
I
V
V
V
V
V
CONT
IN
)
IN
OUT
IN
OUT
F
=
( ) ( )
(
+
(
+
+
)
2
2
4
Minimum inductor discontinuous mode:
)(
( )( )
L
V
I
f I
MIN
OUT
OUT
2
P
=
(
)
2
Minimum inductor continuous mode:
L
V
V
f V
( )
V
I
I
V
V
V
MIN
IN
OUT
IN
OUT
P
OUT
OUT
F
IN
=
( )(
)
+
(
)
+
+
(
)
2
1
For the example above, with maximum load current of
0.25A:
I
A
CONT
=
( ) ( )
)
(
+ +
(
)
=
4 5 5 5 5 05
037
2
2
.
This says that discontinuous mode can be used and the
minimum inductor needed is found from:
( )(
L
H
MIN
=
)
( )
=
2 5 025
500 10
15
.
22
.
μ
3
2
.
·
In practice, the inductor should be increased by about
30% over the calculated minimum to handle losses and
variations in value. This suggests a minimum inductor of
3
μ
H for this application, but looking at the ripple voltage
chart shows that output ripple voltage could be reduced by
a factor of two by using a 15
μ
H inductor. There is no rule
相關(guān)PDF資料
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