參數(shù)資料
型號: M64283FP
廠商: Mitsubishi Electric Corporation
英文描述: Image Sensor (Artificial Retina Chip)
中文描述: 圖像傳感器(人造視網(wǎng)膜芯片)
文件頁數(shù): 25/36頁
文件大?。?/td> 320K
代理商: M64283FP
Mitsubishi Integrated Circuit <Linear IC>
M64283FP
Image Sensor (Artificial Retina Chip)
25/
35
Specifications and information in this document are subject to change without notice.
Ver. 2. 2. 3
07/22/1998
Semiconductor Technical Data
MITSUBISHI
12.10. Random Access Function
12.10.1. Random Access
The whole image is divided into 16 x 16 block areas in which minimum block consists of 8 x 8 pixels, a
start block position (x, y) can be specified by the ST register (8 bits) and an end block position (x', y') by the
END register (8 bits). The access area is specified when coordinate data has been set to both ST and
END registers. To execute the random access, users can choose either positive image or projection
mode. Although the automatic black level calibration is available, clamp circuit is not available in this
mode. Therefore, the CL register must be set to "H". When the random access is executed, both READ
and STRB are also output.
12.10.2. Block Diagram
Figure 17 shows the block diagram of the chip. The lower 4 bits of the ST register indicate the x
coordinate of a start block, and the higher 4 bits indicate the y coordinate of the start block (x = ST [3:0], y =
ST [7:4]). Similarly, the lower 4 bits of the END register indicate the x coordinate of an end block, and the
higher 4 bits indicate the y coordinate of the end block (x' = END [3:0], y' = END [7:4]). An initial value of
ST and END register is 00Hex when the random access starts. In this case, all the pixels are accessed
((x, y) = (0, 0), (x', y') = (16, 16)). The end block coordinate must be greater than the start block coordinate
(x'>x or y'>y). If this condition is not satisfied, the end block coordinate becomes 16.
Horizontal control
V
C
V
X-scanner
Horizontal control circuit for reading
Output signal
Access area
x =ST[3:0],x’=END[3:0]
y=ST[7:4],y’=END[7:4]
x=ST[3:0],x’=END[3:0]
x x’
(16,16)
y
y’
y
y’
(0,0)
y=ST[7:4],y’=END[7:4]
(x,y)
(x’,y’)
x x’
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