參數(shù)資料
型號: OP492GS
廠商: Analog Devices Inc
文件頁數(shù): 5/20頁
文件大小: 0K
描述: IC OPAMP GP 4MHZ QUAD 14SOIC
標(biāo)準(zhǔn)包裝: 56
放大器類型: 通用
電路數(shù): 4
轉(zhuǎn)換速率: 4 V/µs
增益帶寬積: 4MHz
電流 - 輸入偏壓: 375nA
電壓 - 輸入偏移: 1400µV
電流 - 電源: 1mA
電流 - 輸出 / 通道: 10.5mA
電壓 - 電源,單路/雙路(±): 4.5 V ~ 33 V,±2.25 V ~ 16.5 V
工作溫度: -40°C ~ 125°C
安裝類型: 表面貼裝
封裝/外殼: 14-SOIC(0.154",3.90mm 寬)
供應(yīng)商設(shè)備封裝: 14-SOIC
包裝: 管件
OP292/OP492
Rev. C | Page 13 of 20
APPLICATIONS INFORMATION
PHASE REVERSAL
The OP492 has built-in protection against phase reversal when
the input voltage goes to either supply rail. In fact, it is safe for
the input to exceed either supply rail by up to 0.6 V with no risk
of phase reversal. However, the input should not go beyond the
positive supply rail by more than 0.9 V; otherwise, the output
will reverse phase. If this condition occurs, the problem can be
fixed by adding a 5 kΩ current limiting resistor in series with
the input pin. With this addition, the input can go to more than
5 V beyond the positive rail without phase reversal.
An input voltage that is as much as 5 V below the negative rail
will not result in phase reversal.
OP492
2k
5V
0V
11.8V p-p
1V
90
100
10
5s
0%
00
310
-03
4
Figure 34. Output Phase Reverse If Input Exceeds
the Positive Supply (V+) by More Than 0.9 V
2k
5V
0V
10V p-p
1V/DIV
OP492
00
31
0-
03
5
4ms/DIV
Figure 35. No Negative Rail Phase Reversal, Even with Input Signal
at 5 V Below Ground
POWER SUPPLY CONSIDERATIONS
The OP292/OP492 are designed to operate equally well at single
+5 V or ±15 V supplies. The lowest supply voltage recommended
is 4.5 V.
It is a good design practice to bypass the supply pins with a
0.1 μF ceramic capacitor. It helps improve filtering of high
frequency noise.
For dual-supply operation, the negative supply (V) must be
applied at the same time, or before V+. If V+ is applied before V,
or in the case of a loss of the V supply, while either input is
connected to ground or another low impedance source, excessive
input current may result. Potentially damaging levels of input
current can destroy the amplifier. If this condition can exist,
simply add a l kΩ or larger resistor in series with the input to
eliminate the problem.
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