2
SP6832DS/04 SP6832 High Speed, High Efficiency Voltage Inverter Copyright 2000 Sipex Corporation
SPECIFICATIONS FOR THE SP6832
V
= +5.0V, C1 = C2 = C3 = 0.33
μ
F and T
= 25
o
C unless otherwise noted. The circuit found in
Figure 14
was
used to obtain the following typical performance characteristics (unless otherwise noted).
NOTE 1
: V
OUT
= -V
IN
+200mV
NOTE 2
: Capacitors are approximately 20% of the output impedance where ESR =
NOTE 3
: Power Efficiency (Ideal) =
V
OUT
x I
OUT
-V
IN
x (-V
IN
/R
L
)
NOTE 4
: Power Efficiency (Actual) =
V
OUT
x I
OUT
V
IN
x I
IN
ABSOLUTE MAXIMUM RATINGS
These are stress ratings only and functional operation of the device at
these ratings or any other above those indicated in the operation sections
of the specifications below is not implied. Exposure to absolute maximum
rating conditions for extended periods of time may affect reliability.
V
IN
.....................................................................................-0.3V to +5.6V
V
OUT
...................................................................................-5.6V to +0.3V
V
OUT
Short Circuit to GND.................................................Indefinite
I
...................................................................................................50mA
Storage Temperature.....................................................-65C to +150C
Power Dissipation per Package
5-pin SOT (derate 4.35mW/
o
C above +70
o
C).............................400mW
Lead Temperature (Soldering)....................................................300
o
C
ESD Rating...............................................2kV Human Body Model
R
E
T
E
M
A
R
A
P
.
N
I
M
.
P
Y
T
.
X
A
M
S
T
N
U
S
N
O
I
D
N
O
C
e
g
a
V
a
V
m
u
m
y
p
i
u
S
M
e
g
4
6
8
5
1
3
V
R
L
R
L
k
k
0
0
1
1
=
=
T
,
T
,
B
M
A
1
°
e
N
+
o
,
C
C
°
5
0
2
+
4
=
=
B
M
A
C
5
8
°
t
e
C
y
p
u
S
7
4
A
m
T
B
M
A
0
4
=
o
5
8
+
o
C
o
=
L
R
,
C
e
c
n
a
e
R
t
p
O
9
1
5
4
I
T
U
O
2
e
N
,
A
m
5
2
o
A
m
5
=
y
c
n
e
u
q
e
F
r
s
O
0
0
3
0
0
5
0
5
7
z
H
k
y
c
n
e
E
n
o
v
n
o
C
e
g
a
V
5
9
9
9
%
R
L
=
)
e
d
y
c
n
e
E
r
w
o
P
7
9
%
I
T
U
O
3
e
N
,
A
m
5
=
)
u
A
(
y
c
n
e
E
r
w
o
P
7
8
%
I
T
U
O
4
e
N
,
A
m
5
=
∞
∞
1
f
OSC
x C