參數(shù)資料
型號: TJA1020_5
廠商: NXP Semiconductors N.V.
英文描述: LIN transceiver
中文描述: LIN收發(fā)器
文件頁數(shù): 13/24頁
文件大?。?/td> 105K
代理商: TJA1020_5
2002 Jul 17
13
Philips Semiconductors
Product specification
LIN transceiver
TJA1020
Notes
1.
All parameters are guaranteed over the virtual junction temperature by design, but only 100% tested at 125
°
C
ambient temperature for dies on wafer level and above this for cased products 100% tested at 25
°
C ambient
temperature, unless otherwise specified.
For bare die, all parameters are only guaranteed if the backside of the bare die is connected to ground.
If V
BAT
is higher than 12 V, the battery current increases due to the internal LIN termination resistor. The minimum
2.
3.
value of this resistor is 20 k
. The maximum current increase is therefore:
4.
; see Fig.6
5.
; see Fig.6
t
f(slope)(norm)(dom)
normal slope fall time LIN
(100% to 0%)
normal slope mode;
C
L
= 6.8 nF;R
L
= 660
;
V
BAT
= 12 V; transition
from recessive to
dominant; note 4
normal slope mode;
C
L
= 6.8 nF;R
L
= 660
;
V
BAT
= 12 V; transition
from dominant to
recessive; note 5
normal slope mode;
C
L
= 6.8 nF;R
L
= 660
;
V
BAT
= 12 V;
t
f(slope)(dom)
t
r(slope)(rec)
low slope mode;
C
L
= 10 nF; R
L
= 500
;
V
BAT
= 12 V; note 4
low slope mode;
C
L
= 10 nF; R
L
= 500
;
V
BAT
= 12 V; note 5
sleep mode
12
22.5
μ
s
t
r(slope)(norm)(rec)
normal slope rise time
LIN (0% to 100%)
12
22.5
μ
s
t
slope(norm)
normal slope symmetry
4
0
+4
μ
s
t
f(slope)(low)(dom)
low slope fall time LIN
(100% to 0%)
30
62
μ
s
t
r(slope)(low)(rec)
low slope rise time LIN
(0% to 100%)
30
62
μ
s
t
BUS
dominant time for
wake-up via bus
dominant time for
wake-up via pin NWAKE
time period for mode
change from sleep or
standby mode into
normal/low slope mode
time period for mode
change from normal/low
slope mode into sleep
mode
TXD dominant time out
30
70
150
μ
s
t
NWAKE
sleep mode
7
20
50
μ
s
t
gotonorm
2
5
10
μ
s
t
gotosleep
2
5
10
μ
s
t
dom
V
TXD
= 0 V
6
12
20
ms
SYMBOL
PARAMETER
CONDITIONS
MIN.
TYP.
MAX.
UNIT
I
BAT increase
)
V
-------------------------------
12 V
20 k
=
t
f(slope)(dom)
t
------------------------------------------------t
40%
=
(
)
0.55
VLIN
95%
=
(
)
(
)
=
t
r(slope)(rec)
t
---------------------------------------------------------------------------------
60%
=
(
)
t
5%
=
(
)
(
)
0.55
=
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