參數(shù)資料
型號: TPA751GQS
廠商: TEXAS INSTRUMENTS INC
元件分類: 音頻/視頻放大
英文描述: 0.7 W, 1 CHANNEL, AUDIO AMPLIFIER, PBGA24
封裝: 3 X3 MM, PLASTIC, BGA-24
文件頁數(shù): 6/32頁
文件大?。?/td> 910K
代理商: TPA751GQS
TPA751
700mW MONO LOW VOLTAGE AUDIO POWER AMPLIFIER
WITH DIFFERENTIAL INPUTS
SLOS336C DECEMBER 2000 REVISED OCTOBER 2002
14
POST OFFICE BOX 655303
DALLAS, TEXAS 75265
APPLICATION INFORMATION
BTL amplifier efficiency (continued)
Although the voltages and currents for SE and BTL are sinusoidal in the load, currents from the supply are very
different between SE and BTL configurations. In an SE application, the current waveform is a half-wave rectified
shape, whereas in BTL it is a full-wave rectified waveform. This means RMS conversion factors are different.
Keep in mind that for most of the waveform both the push and pull transistors are not on at the same time, which
supports the fact that each amplifier in the BTL device only draws current from the supply for half the waveform.
The following equations are the basis for calculating amplifier efficiency.
Efficiency of a BTL amplifier
+
P
L
P
SUP
(3)
where
(4)
P
L +
V
L
rms2
R
L
, and V
LRMS +
V
P
2
, therefore, P
L +
V
P
2
2R
L
PL = Power delivered to load
PSUP = Power drawn from power supply
VLRMS = RMS voltage on BTL load
RL = Load resistance
VP = Peak voltage on BTL load
IDDavg = Average current drawn from the
power supply
VDD = Power supply voltage
ηBTL = Efficiency of a BTL amplifier
and PSUP + VDD IDDavg and IDDavg +
1
p
0
V
P
R
L
sin(t) dt
+ 1p
V
P
R
L
[cos(t)]
p
0 +
2V
P
p R
L
therefore,
P
SUP +
2V
DD
V
P
p R
L
substituting PL and PSUP into equation 7,
Efficiency of a BTL amplifier
+
V
P
2
2R
L
2V
DD VP
p R
L
+
p V
P
4V
DD
V
P +
2P
L
R
L
h
BTL +
p 2P
L
R
L
4V
DD
where
therefore,
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