參數(shù)資料
型號(hào): VSC7940RP
廠商: VITESSE SEMICONDUCTOR CORP
元件分類: 其它接口
英文描述: SONET/SDH 3.125Gb/s Laser Diode Driver with Automatic Power Control
中文描述: SPECIALTY INTERFACE CIRCUIT, PQFP32
封裝: 5 X 5 MM, TQFP-32
文件頁數(shù): 10/16頁
文件大?。?/td> 167K
代理商: VSC7940RP
VITESSE
Preliminary Data Sheet
VSC7940
SONET/SDH 3.125Gb/s
Laser Diode Driver with Automatic Power Control
Page 10
G52357-0, Rev 3.2
05/11/01
VITESSE
SEMICONDUCTOR CORPORATION
741 Calle Plano
Camarillo, CA 93012
Tel: (800) VITESSE
FAX: (805) 987-5896
Email: prodinfo@vitesse.com
Internet: www.vitesse.com
Reducing Pattern-Dependent Jitter
Three design values significantly affect pattern-dependent jitter; the capacitor at CAPC, the pull-up induc-
tor at the output (L
P
), and the AC-coupling capacitor at the output (C
D
). As previously stated, the recommended
value for the capacitor at CAPC is 0.1
μ
F. This results in a 10kHz loop bandwidth which makes the pattern-
dependent jitter from the APC loop negligible.
For 2.5Gb/s data rates, the recommended value for C
D
is 0.056
μ
F. The time constant at the output is domi-
nated by L
P
. The variation in the peak voltage should be less that 12% of the average voltage over the maximum
consecutive identical digit (CID) period. The following equation approximates this time constant for a CID
period, t, of 100UI = 40ns:
τ
LP
= -t / ln(1-12%) = 7.8t = L
P
/ 25
Therefore, the inductor L
P
should be a 7.8
μ
H SMD ferrite bead inductor for this case.
Input/Output Considerations
Although the VSC7940 is PECL-compatible, this is not required to drive the device. The inputs must only
meet the common-mode voltage and differential voltage swing specifications.
Power Consumption
The following equation provides the device supply current (I
S
) in terms of quiescent current (I
Q
), modula-
tion current (I
MOD
), and bias current (I
BIAS
):
I
S
=
19mA
+ 0.4 * I
MOD
+ 0.16 * I
BIAS
This equation may be used to determine the estimated power dissipation:
P
DIS
= V
CC
* I
S
For example, if the device were operated at 5V with a 30mA modulation current and a 10mA bias current,
the supply current would be:
I
S
= 19mA + 0.4 * 30mA + 0.16 * 10mA = 33mA
This corresponds to a power dissipation of 5V * 33mA = 165mW.P
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