參數(shù)資料
型號(hào)： AD9516-1BCPZ
廠商： Analog Devices Inc
文件頁(yè)數(shù)： 39/80頁(yè)
文件大?。?/td> 0K
描述： IC CLOCK GEN 2.5GHZ VCO 64-LFCSP
標(biāo)準(zhǔn)包裝： 1
類型： 時(shí)鐘發(fā)生器，扇出配送
PLL： 是
輸入： 時(shí)鐘
輸出： CMOS，LVDS，LVPECL
電路數(shù)： 1
比率 - 輸入:輸出： 1:14
差分 - 輸入:輸出： 是/是
頻率 - 最大： 2.65GHz
除法器/乘法器： 是/無(wú)
電源電壓： 3.135 V ~ 3.465 V
工作溫度： -40°C ~ 85°C
安裝類型： 表面貼裝
封裝/外殼： 64-VFQFN 裸露焊盤，CSP
供應(yīng)商設(shè)備封裝： 64-LFCSP-VQ（9x9）
包裝： 托盤
產(chǎn)品目錄頁(yè)面： 776 (CN2011-ZH PDF)
配用： AD9516-1/PCBZ-ND - BOARD EVALUATION FOR AD9516-1
AD9516-1
Data Sheet
Rev. C | Page 44 of 80
Duty Cycle and Duty-Cycle Correction (Divider 3 and
Divider 4)
The same duty cycle and DCC considerations apply to Divider 3
and Divider 4 as to Divider 0, Divider 1, and Divider 2 (see the
however, with these channel dividers, the number of possible
configurations is even more complex.
Duty-cycle correction on Divider 3 and Divider 4 requires the
following channel divider conditions:
An even DX.Y must be set as MX.Y = NX.Y (low cycles = high
cycles).
An odd DX.Y must be set as MX.Y = NX.Y + 1 (the number of
low cycles must be one greater than the number of high
cycles).
If only one divider is bypassed, it must be the second
divider, X.2.
If only one divider has an even divide by, it must be the
second divider, X.2.
The possibilities for the duty cycle of the output clock from
Divider 3 and Divider 4 are shown in Table 40 through Table 44
Table 40. Divider 3, Divider 4 Duty Cycle; VCO Divider
Used; Duty Cycle Correction Off (DCCOFF = 1)
VCO
Divider
DX.1
DX.2
Output Duty
Cycle
NX.1 + MX.1 + 2
NX.2 + MX.2 + 2
Even
1
50%
Odd = 3
1
33.3%
Odd = 5
1
40%
Even
Even, odd
1
(NX.1 + 1)/
(NX.1 + MX.1 + 2)
Odd
Even, odd
1
(NX.1 + 1)/
(NX.1 + MX.1 + 2)
Even
Even, odd
(NX.2 + 1)/
(NX.2 + MX.2 + 2)
Odd
Even, odd
(NX.2 + 1)/
(NX.2 + MX.2 + 2)
Table 41. Divider 3, Divider 4 Duty Cycle; VCO Divider Not
Used; Duty Cycle Correction Off (DCCOFF = 1)
Input Clock
Duty Cycle
DX.1
DX.2
Output
Duty Cycle
NX.1 + MX.1 + 2
NX.2 + MX.2 + 2
50%
1
50%
X%
1
X%
50%
Even, odd
1
(NX.1 + 1)/
(NX.1 + MX.1 + 2)
X%
Even, odd
1
(NX.1 + 1)/
(NX.1 + MX.1 + 2)
50%
Even, odd
(NX.2 + 1)/
(NX.2 + MX.2 + 2)
X%
Even, odd
(NX.2 + 1)/
(NX.2 + MX.2 + 2)
Table 42. Divider 3, Divider 4 Duty Cycle; VCO Divider
Used; Duty Cycle Correction Is On (DCCOFF = 0); VCO
Divider Input Duty Cycle = 50%
VCO
Divider
DX.1
DX.2
Output
Duty Cycle
NX.1 + MX.1 + 2
NX.2 + MX.2 + 2
Even
1
50%
Odd
1
50%
Even
Even (NX.1 = MX.1)
1
50%
Odd
Even (NX.1 = MX.1)
1
50%
Even
Odd (MX.1 = NX.1 + 1)
1
50%
Odd
Odd (MX.1 = NX.1 + 1)
1
50%
Even
Even (NX.1 = MX.1)
Even (NX.2 = MX.2)
50%
Odd
Even (NX.1 = MX.1)
Even (NX.2 = MX.2)
50%
Even
Odd (MX.1 = NX.1 + 1)
Even (NX.2 = MX.2)
50%
Odd
Odd (MX.1 = NX.1 + 1)
Even (NX.2 = MX.2)
50%
Even
Odd (MX.1 = NX.1 + 1)
Odd (MX.2 = NX.2 + 1)
50%
Odd
Odd (MX.1 = NX.1 + 1)
Odd (MX.2 = NX.2 + 1)
50%
Table 43. Divider 3, Divider 4 Duty Cycle; VCO Divider
Used; Duty Cycle Correction On (DCCOFF = 0); VCO
Divider Input Duty Cycle = X%
VCO
Divider
DX.1
DX.2
Output
Duty Cycle
NX.1 + MX.1 + 2
NX.2 + MX.2 + 2
Even
1
50%
Odd = 3
1
(1 + X%)/3
Odd = 5
1
(2 + X%)/5
Even
(NX.1 = MX.1)
1
50%
Odd
Even
(NX.1 = MX.1)
1
50%
Even
Odd
(MX.1 = NX.1 + 1)
1
50%
Odd = 3
Odd
(MX.1 = NX.1 + 1)
1
(3NX.1 + 4 + X%)/
(6NX.1 + 9)
Odd = 5
Odd
(MX.1 = NX.1 + 1)
1
(5NX.1 + 7 + X%)/
(10NX.1 + 15)
Even
(NX.1 = MX.1)
Even
(NX.2 = MX.2)
50%
Odd
Even
(NX.1 = MX.1)
Even
(NX.2 = MX.2)
50%
Even
Odd
(MX.1 = NX.1 + 1)
Even
(NX.2 = MX.2)
50%
Odd
(MX.1 = NX.1 + 1)
Even
(NX.2 = MX.2)
50%
Even
Odd
(MX.1 = NX.1 + 1)
Odd
(MX.2 = NX.2 + 1)
50%
Odd = 3
Odd
(MX.1 = NX.1 + 1)
Odd
(MX.2 = NX.2 + 1)
(6NX.1NX.2 + 9NX.1 +
9NX.2 + 13 + X%)/
(3(2NX.1 + 3)
(2NX.2 + 3))
Odd = 5
Odd
(MX.1 = NX.1 + 1)
Odd
(MX.2 = NX.2 + 1)
(10NX.1NX.2+ 15NX.1 +
15NX.2 + 22 + X%)/
(5(2 NX.1 + 3)
(2 NX.2 + 3))
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