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參數(shù)資料
| 型號： | IRU3055 |
| 廠商： | International Rectifier |
| 英文描述： | 5-BIT PROGRAMMABLE 3-PHASE SYNCHRONOUS BUCK CONTROLLER IC |
| 中文描述： | 5位可編程3相位同步降壓控制器IC |
| 文件頁數(shù)： | 14/26頁 |
| 文件大?。?/td> | 352K |
| 代理商： | IRU3055 |
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14
Rev. 1.4
08/13/02
IRU3055
www.irf.com
(5) MOSFET Selection
By equation (9), the RMS current of high side
MOSFET is given as:
Select MOSFET from International Rectifier
IRF3704S with D-2 pak, which will result to:
For low side MOSFET:
I
RMS(LO)
= (1-D)
×
I
OUT
/m
D = V
OUT
/V
IN
= 1.5/12 = 0.125
I
RMS(LO)
= (1-0.125)
×
60/3 = 19A
Select MOSFET from International Rectifier
IRF3711S with D-2 package, which will result to:
(6) Over Current Setting
By equation (3), over current limit is set by R
SET
. The
current limit should be at least 150% of the nominal
output current. Set I
MAX
=90A and 30A for each phase.
For low side MOSFET, R
DS(ON)
=6m
and 9m
at
150
8
C. The over current setting resistor is given by:
(7) Compensation Design
For detailed explanation, please see IRU3037 data
sheet. Select bandwidth of the system to be 1/10 of
switching frequency that is 15KHz:
The compensation resistor can be calculated as:
Where Vosc is the ramp peak voltage and g
m
is the
transconductance of the error amplifier. From the
data sheet:
Vosc = 2V
g
m
= 720
μ
mho
The compensator capacitor is given as:
R
RDS(ON)
= 9m
and 110A I
DS
current
R
DS(ON)(LO)
= 6m
and 110A current
Fo = 2
×
3.14
×
15KHz = 94KHz
Rc = Vosc
×
Fo
×
L/(V
IN
×
ESR
×
g
m
)
I
RMS(HI)
= D
×
I
OUT
/m
I
RMS(HI)
= (V
OUT
/V
IN
)
×
I
OUT
/m
D = 1.5/12 = 0.125
I
RMS
= 0.125
×
60A/3 = 7.1A
Cc = (L
×
C
OUT
) /0.75/Rc
Cc = (1
μ
H
×
21600
μ
F) /0.75/12K
= 16.3nF
Select C12=Cc=22nF
R
SET
= I
MAX
×
R
DS(ON)
/3/160
μ
A
R
SET
= 90A
×
9m
/3/160
μ
A = 1.7K
Select R
SET
= 2.2K
Rc = 2
×
94KHz
×
1
μ
H/(12
×
1.6m
×
720
μ
mho)
Rc = 12K
. Select R6=Rc=12.7K
Design Example
In the demo-board, the condition is as follows:
Output voltage regulation is within 100mV during tran-
sient.
(1) Select Switching Frequency
According to Figure 10 and equation (5), the oscilla-
tor selection resistor is given by:
Rt
7500/150 = 50K
From Figure 10, select Rt=47K
(2) Soft-Start Capacitor
For 1.5V output, V
SET
=1.5V. The soft-start time of
the converter can be estimated from equation (4):
t
START
= (V
SET
+0.7V)
×
Css/10
μ
A
If t
START
=20ms, then:
Css = 20ms
×
10
μ
A/(1.5V+0.7V) = 95nF
Choose Css=0.1
μ
F
(3) Output Inductor and Capacitor
Select the current ripple LIR=40%, by equation (7):
L>V
OUT
×
(V
IN
-V
OUT
)/(Fs
×
V
IN
×
LIR
×
I
OUT
/m)
L>1.5
×
(12-1.5)/(150K
×
12
×
40%
×
60A/3)=1.1
μ
H
Select core from Micrometal, T60-18 with 6 turns
#14 AWG wire, which gives 1
μ
H inductor, 15A RMS
and 25A saturation current. The DC resistor of in-
ductor is 1.6m
.
L = 1
μ
H and R
L
= 1.6m
The output capacitor is based on ESR. Suppose
the maximum allowed voltage droop for 60A load is:
Select 8 Panasonic capacitors. EEUFJ0J272U with
2700
μ
F and 13m
ESR each. The total:
C
OUT
= 8
×
2700
μ
F = 21600
μ
F
ESR = 13m
/8 = 1.6m
(4) Senseless Inductor Current Sensing
With equation (1), we select the inductor sensing
network which has a time constant:
R2
×
C8 = 2
×
L/R
L
Select: C8 = 1
μ
F
R2 = 2
×
1
μ
H/(1.6m
×
1uF) = 1.25K
Select R2, R4 and R5 = 1.5K
Fs = 150KHz for each phase
V = 100mV
ESR <
V/
i = 100mV/60A = 1.66m
V
IN
=12V, V
OUT
=1.5V and I
OUT
=60A
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