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I
E0
RL1
L1
I
E
IS
RL
I
S0
V
LS
I
SRL
C1
D7
V
E1
C5
I
Et
V
E
SW1
A
Figure67
VI - RINGER FEATURES
(continued)
VI.3 - Ring Frequency Generator
The ring frequencyvalueswhichcan be generated
are thosegiven Page 45 of thisapplication note.
On the Table given at Page45, only the frequency
values for n > 15 are given, the frequency values
from n = 1 (1000000)to n =15 (1001111)are also
accessible, if it is neccessary to generate a fre-
quency higher than 1645Hz.
VI.4 - Output Power Optimization
The power available on Pin LSOUT (Pin 44) de-
pends on :
- The countryrequires :
Minimum input ac levelin test conditions.
Ringimpedance.
Takingin accountthese mainrequeststhepower
on Pin LSOUT (Pin 44) is optimized through the
resistor R40connected on Pin RCO (Pin 41).
- The yieldof theswitch mode powersupply.
The principal parameters which influence the
yieldare :
D7 V
BE
value.
T1 V
CEsat
and base current values (the maxi-
mum I
C PEAK
valueis 100mA).
L1 serial resistor value.
Current consumption on Pin V
ZP
(Pin 38) and
on PinRSU (Pin 40).
Biascurrent consumptionon Pin V
LS
This paragraphgivesinformation on :
- The switchmode power supply concept.
- The switchmode power supply yield.
- The ringoutputpoweroptimizationonPinLSOUT
(Pin 44).
VI.4.1 - Switch Mode Power Supply Concept
Aftertheringbridge,theswitch modepowersupply
concept is representedin Figure 67.
V
E
Input voltage equivalentto V
RING1
V
E1
Input voltage after the switch SW1
I
E
Mean inputcurrent
V
S
Output voltage at Pin V
LS
(Pin1)
I
S
Mean outputcurrent
V
D
Voltage across D7 when it is in
forward mode
I
E0
Primary biascurrent
I
S0
Secondarybias current
RL1
Resistive part of the coil L1
SwitchSW1
- V
CEsat
of T1 PNP
- I
B1
, T1base current
- t
D
, T1desaturationtime
- V
E1
= V
E
- V
CEsat(T1)
Figure 68 givesthe voltage,V
E1
, the current in the
coil,I
SELF
, thecurrent in D7,I
DIODE
andthe current
in the switch SW1given by C6, I
CAPA
.
Thevalueofthemaximumcurrentinthecoilisfixed
by t
ON
and t
OFF
depends on RL. When RL de-
creases, t
ON
increases. The coil value should be
calculatedsothatthe current inthe coilreachesthe
zerovalue with the minimum charge.
I
Max.
=
t
ON
V
E1
V
LS
L
(1)
L is the value of the coil L1.
The ratio between t
ON
and t
OFF
is :
t
ON
t
OFF
=
V
D
+
V
LS
The output current I
S
is :
I
S
=
I
Max.
V
E1
V
LS
(2)
2
t
ON
+
t
OFF
t
(3)
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