參數(shù)資料
型號(hào)： TS4962MEIJT
廠商： STMICROELECTRONICS
元件分類： 音頻／視頻放大
英文描述： 3 W, 1 CHANNEL, AUDIO AMPLIFIER, PBGA9
封裝： ROHS COMPLIANT, FCP-9
文件頁(yè)數(shù)： 22/41頁(yè)
文件大?。?/td> 1104K
代理商： TS4962MEIJT
TS4962M
Application information
29/41
5.3
Common mode feedback loop limitations
As explained previously, the common mode feedback loop allows the output DC bias voltage
to be averaged at VCC/2 for any DC common mode bias input voltage.
However, due to Vicm limitation in the input stage (see Table 2: Operating conditions on
page 3), the common mode feedback loop can ensure its role only within a defined range.
This range depends upon the values of VCC and Rin (AVdiff). To have a good estimation of
the Vicm value, we can apply this formula (no tolerance on Rin):
with
and the result of the calculation must be in the range:
Due to the +/-9% tolerance on the 150k
Ω resistor, it’s also important to check Vicm in these
conditions:
If the result of Vicm calculation is not in the previous range, input coupling capacitors must
be used (with VCC from 2.4V to 2.5V, input coupling capacitors are mandatory).
For example:
With VCC =3V, Rin = 150k and VIC = 2.5V, we typically find Vicm = 2V and this is lower than
3V - 0.8V = 2.2V. With 136.5k
Ωwe find 1.97V, and with 163.5kΩwe have 2.02V. So, no input
coupling capacitors are required.
5.4
Low frequency response
If a low frequency bandwidth limitation is requested, it is possible to use input coupling
capacitors.
In the low frequency region, Cin (input coupling capacitor) starts to have an effect. Cin forms,
with Rin, a first order high-pass filter with a -3dB cut-off frequency:
So, for a desired cut-off frequency we can calculate Cin,
with Rin in Ω and FCL in Hz.
V
icm
V
CC
R
in
×
2V
IC
×
150k
Ω
×
+
2R
in
150k
Ω
+
()
×
------------------------------------------------------------------------------
(V)
=
V
IC
In
+
In
-
+
2
---------------------
(V)
=
0.5V
V
icm
V
CC
0.8V
–
≤≤
V
CC
R
in
×
2V
IC
×
136.5k
Ω
×
+
2R
in
136.5k
Ω
+
()
×
-----------------------------------------------------------------------------------
V
icm
V
CC
R
in
×
2V
IC
×
163.5k
Ω
×
+
2R
in
163.5k
Ω
+
()
×
-----------------------------------------------------------------------------------
≤≤
F
CL
1
2
π R
in
×
C
in
×
--------------------------------------
(Hz)
=
C
in
1
2
π R
in
×
F
CL
×
----------------------------------------
(F)
=
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