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參數(shù)資料
| 型號(hào)： | FA3687V |
| 廠商： | FUJI ELECTRIC CO LTD |
| 元件分類： | 穩(wěn)壓器 |
| 英文描述： | 0.4 A DUAL SWITCHING CONTROLLER, 1500 kHz SWITCHING FREQ-MAX, PDSO16 |
| 封裝： | 1.10 MM HEIGHT, TSSOP-16 |
| 文件頁(yè)數(shù)： | 9/18頁(yè) |
| 文件大?。?/td> | 378K |
| 代理商： | FA3687V |
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FA3687V
17
Fig. 11
The negative output voltage of DC-to-DC converter (inverting) is
determined by:
The ratio of resistances is determined by:
(Use the absolute value of the Vout2 voltage.)
When R5 = R6,
Connect the SEL1 and SEL2 pin to GND or VREG surely.
6. Restriction of external discrete components and
recommended operating conditions
To achieve a stable operation of the IC, the value of external
discrete components connected to VCC, VREG, CS, CP pins
should be within the recommended operating conditions. And
the voltage and the current applied to each pin should be also
within the recommended operating conditions. If the pin voltage
of OUT1, OUT2, or VREG becomes higher than the VCC pin
voltage, the current flows from the pins to the VCC pin because
parasitic three diodes exist between the VCC pin and these
pins. Be careful not to allow this current to flow.
7. Loss calculation
Since it is hard to measure IC loss directly, the calculation to
obtain the approximate loss of the IC connected directly to a
MOSFET is described below.
When the supply voltage is VCC, the current consumption of the
IC is ICCA, the total input gate charge of the driven MOSFET is
Qg and the switching frequency is fsw, the total loss Pd of the
IC can be calculated by:
Pd
VCC
(ICCA + Qg
fsw).
The value in this expression is influenced by the effects of the
dependency of supply voltage, the characteristics of
temperature, or the tolerance of parameter. Therefore, evaluate
the appropriateness of IC loss sufficiently considering the range
of values of above parameters under all conditions.
Example
ICCA=2.5mA for VCC=3.3V in the case of a typical IC from the
characteristic curves. Qg=6nC, fsw=500kHz, the IC loss “Pd” is
as follows.
Pd
3.3
(2.5mA + 6nC
500kHz)
18.2mW
If two MOSFETs are driven under the same condition for 2
channels, Pd is as follows:
Pd
3.3
{2.5mA+2
(6nC
500kHz)} = 28.1mW
IN1-
FB1
Vout1
R2
R1
SEL1
VREG
OUT1
Vout1
9
16
15
14
+
VREF
(1.0V)
IN1-
FB1
Vout1
R2
R1
SEL1
GND
OUT1
Vout1
9
16
15
14
+
VREF
(1.0V)
Buck
Boost
5
4
3
13
VREG
IN2+
IN2-
FB2
Vout2
R3
R4
R5
R6
2
SEL2
VREG
OUT2
8
Vout2
V1
5
4
3
13
VREG
IN2+
IN2-
FB2
Vout2
R3
R4
R5
R6
2
SEL2
VREG
OUT2
8
Vout2
V1
5
4
3
13
VREG
IN2+
IN2-
FB2
Vout2
R3
R4
R5
R6
2
SEL2
GND
OUT2
8
Vout2
V1
Buck
Boost
Inverting
()
Vout2 = VREG
R3 – R4
2R3
R3
=
VREG – V1
R4
Vout2 + V1
Vout2 =
R3 + R4
V1 –
R4
VREG
R3
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