FN6314.2 July 15, 2010 best choice. These devices are available from such vendors as Panasonic and Murata. The main specifications include work" />
參數(shù)資料
型號: ISL1219IUZ
廠商: Intersil
文件頁數(shù): 16/24頁
文件大小: 0K
描述: IC RTC LP BATT BACK SRAM 10MSOP
產(chǎn)品培訓(xùn)模塊: Solutions for Industrial Control Applications
標準包裝: 98
類型: 時間事件記錄器
特點: 警報器,閏年,SRAM
存儲容量: 2B
時間格式: HH:MM:SS(12/24 小時)
數(shù)據(jù)格式: YY-MM-DD-dd
接口: I²C,2 線串口
電源電壓: 2.7 V ~ 5.5 V
電壓 - 電源,電池: 1.8 V ~ 5.5 V
工作溫度: -40°C ~ 85°C
安裝類型: 表面貼裝
封裝/外殼: 10-TFSOP,10-MSOP(0.118",3.00mm 寬)
供應(yīng)商設(shè)備封裝: 10-MSOP
包裝: 管件
產(chǎn)品目錄頁面: 1245 (CN2011-ZH PDF)
23
FN6314.2
July 15, 2010
best choice. These devices are available from such vendors
as Panasonic and Murata. The main specifications include
working voltage and leakage current. If the application is for
charging the capacitor from a +5V ±5% supply with a signal
diode, then the voltage on the capacitor can vary from ~4.5V
to slightly over 5.0V. A capacitor with a rated WV of 5.0V
may have a reduced lifetime if the supply voltage is slightly
high. The leakage current should be as small as possible.
For example, a Super Capacitor should be specified with
leakage of well below 1A. A standard electrolytic capacitor
with DC leakage current in the microamps will have a
severely shortened backup time.
Below are some examples with equations to assist with
calculating backup times and required capacitance for the
ISL1219 device. The backup supply current plays a major
part in these equations, and a typical value was chosen for
example purposes. For a robust design, a margin of 30%
should be included to cover supply current and capacitance
tolerances over the results of the calculations. Even more
margin should be included if periods of very warm
temperature operation are expected.
Example 1. Calculating Backup Time Given
Voltages and Capacitor Value
In Figure 23, use CBAT = 0.47F and VDD = 5.0V. With VDD =
5.0V, the voltage at VBAT will approach 4.7V as the diode turns
off completely. The ISL1219 is specified to operate down to
VBAT = 1.8V. The capacitance charge/discharge equation is
used to estimate the total backup time. (Equation 2 and 3):
Rearranging gives
CBAT is the backup capacitance and dV is the change in
voltage from fully charged to loss of operation. Note that
ITOT is the total of the supply current of the ISL1219 (IBAT)
plus the leakage current of the capacitor and the diode, ILKG.
In these calculations, ILKG is assumed to be extremely small
and will be ignored. If an application requires extended
operation at temperatures over +50°C, these leakages will
increase and hence reduce backup time.
Note that IBAT changes with VBAT almost linearly (see
Typical Performance Curves). This allows us to make an
approximation of IBAT, using a value midway between the
two endpoints. The typical linear equation for IBAT vs. VBAT
is shown in Equation 4:
Using this equation to solve for the average current given 2
voltage points gives (Equation 5):
Combining with Equation 3 gives the equation for backup
time (Equation 6):
where:
CBAT = 0.47F
VBAT2 = 4.7V
VBAT1 = 1.8V
ILKG = 0 (assumed minimal)
Solving Equation 5 for this example, IBATAVG = 4.387E-7 A
TBACKUP = 0.47 * (2.9) / 4.38E-7 = 3.107E6 sec
Since there are 86,400 seconds in a day, this corresponds to
35.96 days. If the 30% tolerance is included for capacitor
and supply current tolerances, then worst case backup time
would be:
CBAT = 0.70 * 35.96 = 25.2 days
Example 2. Calculating a Capacitor Value for a
Given Backup Time
Referring to Figure 23 again, the capacitor value needs to be
calculated to give 2 months (60 days) of backup time, given
VDD = 5.0V. As in Example 1, the VBAT voltage will vary from
4.7V down to 1.8V. We will need to rearrange Equation 3 to
solve for capacitance (Equation 7):
Using the terms described above, this equation becomes
(Equation 8):
where:
TBACKUP = 60 days * 86,400 sec/day = 5.18 E6 sec
IBATAVG = 4.387 E-7 A (same as Example 1)
ILKG = 0 (assumed)
VBAT2 = 4.7V
VBAT1 = 1.8V
Solving gives:
CBAT = 5.18 E6 * (4.387 E-7)/(2.9) = 0.784F
If the 30% tolerance is included for tolerances, then worst
case cap value would be:
CBAT = 1.3 *.784 = 1.02F
FIGURE 23. SUPERCAPACITOR CHARGING CIRCUIT
2.7V to 5.5V
VDD
VBAT
GND
1N4148
CBAT
I = CBAT * dV/dT
(EQ. 2)
dT = CBAT * dV/ITOT to solve for backup time.
(EQ. 3)
IBAT = 1.031E-7*(VBAT) + 1.036E-7 Amps
(EQ. 4)
IBATAVG = 5.155E-8*(VBAT2 + VBAT1) + 1.036E-7 Amps
(EQ. 5)
TBACKUP = CBAT * (VBAT2 - VBAT1) / (IBATAVG + ILKG)
(EQ. 6)
seconds
CBAT = dT*I/dV
(EQ. 7)
CBAT = TBACKUP * (IBATAVG + ILKG)/(VBAT2 – VBAT1)
(EQ. 8)
ISL1219
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