參數(shù)資料
型號(hào)： L8574D
英文描述： CAP 15PF 50V 5% C0G SMD-0402 TR-7-PA SN100
中文描述： L8574D電阻用戶線接口電路（SLIC），環(huán)繼電器和保護(hù)（SRP）的為遠(yuǎn)距離和TR - 57應(yīng)用
文件頁數(shù)： 30/36頁
文件大小： 489K
代理商： L8574D
30
Lucent Technologies Inc.
Data Sheet
October 1998
Relay, and Protector (SRP) for Long Loop and TR-57 Applications
L8574D Resistive Subscriber Line Interface Circuit (SLIC), Ring
ac Design
(continued)
Design Equations
(continued)
12-3429.b (F).r3
Figure 12. Initial ac Interface for Complex Termination Between L8574 SLIC and T7504 Codec
Note: dc Blocking Capacitor (C
B
) Not Shown, C
T
and C
R
Separate
V
RN
RECEIVE
INTERFACE
+
–
R
T2
R
RV2
R
HB1
R
GX
GSX
VFXIN
VFRO
1/4 T7504 CODEC
Z
T/R
+
–
V
T/R
I
T/R
+2.4 V
C
R
1/2 L8574
R
GX1
R
RV1
C
T
R
T1
Z
IRP
–
+
AX
V
XMT
L
RP
V
RN
XMT
I
RP
PT
PR
V
BAT
TS
RS
V
BAT
R
1
R
2
C
1
RESISTOR
MODULE
200 k
200 k
100 k
200
200
100 k
1 k
1 k
The Tip/Ring differential current is given by:
The voltage at pin XMT is given by:
The component values in the ac interface of Figure 12
are calculated (for the transmit and receive gains
defined by the respective gain constants K
RX
and K
RCV
,
and for the termination impedance seen in Figure 11)
using the following equations:
Note that the 200
feed resistors contribute 400
to
the termination impedance. The termination impedance
associated with the circuit in Figure 12 consists of this
inherent 400
feeding impedance in parallel with:
I
A negative impedance, where,
I
A positive impedance, where,
The negative and positive impedance terms are used
to adjust the termination impedance from the inherent
400
to any complex termination.
I
T/R
200 I
RP
V
RN
Z
IRP
-----------
–
=
V
XMT
V
T/R
2
–
-------------
=
R
RV1
100R
1
′
K
RCV
100R
′
K
RCV
K
RCV
C
′
100
------------------
=
R
RV2
------------------
=
C
R
-------------------
=
R
R
GX1
400
= 2 x 200
feed resistors
R
GX
2
x
K
TX
R
GX1
=
C
′
100
R
T1
R
T1
+
-----------------------------
R
100
------------
1
600
---------
1
R
1
′
--------
–
=
R
T1
100R
1
′
R
RV1
+
(
)
C
T
--------- 1
GX1
R
------------------
+
+
=
R
T2
R
2
′
C
′
C
T
--------------
=
2
100
---------
x
R
R
GX1
R
T1
+
-----------------------------
R
T2
ω
C
T
-------------
+
R
GX1
-----------------------------
R
T1
+
R
T1
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