32
Lucent Technologies Inc.
Data Sheet
October 1998
Relay, and Protector (SRP) for Long Loop and TR-57 Applications
L8574D Resistive Subscriber Line Interface Circuit (SLIC), Ring
ac Design
(continued)
Design Equations
(continued)
As a practical design example, design the interface for
the following set of requirements:
RX = 0 dB
TX = 0 dB
ZT = 900
Hy = 900
First, calculate the gain constants:
Ko =
= 1.2247
K
RCV
= K
O
10
RX/20
= 1.2247 x 10
0/20
= 1.2247
K
TX
=
10
TX/20
= 0.8165
Second, calculate individual components:
R
RV1
= 73,487
Choose a standard value component:
R
RV1
= 73.2 k
R
RV2
=
= 0
C
R
=
=
Choose R
GX1
= 100 k
:
R
T1
= 0
C
T
=
C
T
=
R
T2
=
= 0
R
GX
= 2 x K
TX
(R
GX1
+ R
T1
)
R
GX
= 2 x 0.8165 (100 k
+ 0)
R
GX
= 163.3 k
Choose a standard value resistor:
R
GX
= 165 k
R
HB
=
R
HB
=
Therefore, for this design example, use the following
values in the circuit shown in Figure 12.
R
T1
= 0 k
R
T2
= 0
R
GX
= 165 k
R
GX1
= 100 k
R
RV1
= 73.2 k
R
RV2
= 0
R
HB1
= 165 k
C
T
=
∞
C
R
=
∞
Figure 15 is the application circuit with the above
values.
----------
----------
=
-------
′
RCV
-----------------------
′
---------------------
∞
GX1
T1
+
--------------------------------
--------------
----------
1
′
---------
–
=
R
T1
+
--------------------------------------
-----------------------
----------
----------
–
=
R
T1
+
--------------------------------------
1.01
=
′
----------
1
T1
--------------
+
1
1
′
RV1
----------------------
+
∞
′
′
T
----------------
R
×
K
TX
K
RCV
----------------------------
165
k
×
0.8165
1.2247
-----------------------------------------
165 k
=